问题解方程题，挺简单，帮忙
7/(x^2+x)+4/(x^2-x)=6/(x-1)
7/(x^2+x)-3/(x-x^2)=1+(7-x^2)/(x^2-1)
7/(x^2+x)+4/(x^2-x)=6/(x-1)
7/(x^2+x)-3/(x-x^2)=1+(7-x^2)/(x^2-1)
答案(1).7/(x^2+x)+4/(x^2-x)=6/(x-1)
去分母得
x(6x^2-5x+3)=0
∵x≠0,
∴6x^2-5x+3=0
△=25-4*3*6<0.
∴原方程无解.
(2).7/(x^2+x)-3/(x-x^2)=1+(7-x^2)/(x^2-1)
去分母,约分得4x-4=0
解得x=1.
去分母得
x(6x^2-5x+3)=0
∵x≠0,
∴6x^2-5x+3=0
△=25-4*3*6<0.
∴原方程无解.
(2).7/(x^2+x)-3/(x-x^2)=1+(7-x^2)/(x^2-1)
去分母,约分得4x-4=0
解得x=1.
